Enigma simulator python3/27/2023 If the rotor start positions are 'FEQ', then they will first be incremented to 'FER' before theįirst letter is enciphered. Is the fact that the rotors increment before each letter is enciphered. One important step that I have not yet mentioned We can see from the table that after the enciphered letter comes back out rotor III at the end, we are left with the letter U. Of the reflector, the letter is sent back through the rotors in the reverse direction (this means the inverse substitution is applied). This is best depicted using a table (for a full description of the rotor wirings for each rotor, see this wikipedia page): IIIĪfter the letter goes through rotors III,II,I it then hits the reflector and undergoes another simple substitution. The letter 'B' is now input through rotor II, where it is replaced by 'J' etc. So after the letter 'A' goes through the rotor, itĬomes out as a 'B'. ABCDEFGHIJKLMNOPQRSTUVWXYZī is replaced with D, C is replaced with F etc. The substitution table for rotor III can be seen below. Each rotor applies a simple substitution operation. Since our rotors are I,II,III moving from left to right, the character A will first go through rotor III. We will assume for now that as the letter 'A' is encipheredĮach rotor is in its start position ('AAA'). The Rotors §Īssume that our rotors are I,II,III moving from left to right, and we are trying to encipher the letter 'A'.
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